Investigation 9: Looking Inside the Box: Properties of the Function y = ex & Investigation 10: The Derivative of y = ex
Step D
You are to estimate the slope of the tangent to the graph at x = 0 by calculating the slopes of various secants to the graph for which one intersection point is (0, 1).
For example, you can find the slope of the secant containing the points
(0, 1) and (0.5, f (o.5)), which is the point (0.5, 1.649).
You might also find the slope of the secant containing the points (0, 1) and (0.1, f (0.1)), which is the point (0.1, 1.105).
Perform similar calculations with the x-coordinate of the second point becoming close to zero.
You should observe that as the second point you choose gets closer and closer to the point (0, 1), the slope of the secant gets closer and closer to one.
Find an expression for the slope of the secant line through the points (0, 1) and (h, eh ).
The resulting expression, you can conclude, also gets closer and closer to one, as h tends to zero. Essentially, this means that as the value of h tends to zero, the expression approaches 1.
The end value of this limiting process is one. This is, of course, the value of the derivative of the function y=exat the point (0, 1).