| Focus J: Using the Laws of LogarithmsTest yourself (solution)      
 Note you may leave the solution in exponential form when
      the exponent is large as in this problem.
 
 
  
           
 An interesting thing happens if we substitute these values
      back into the original equation to determine if the solutions are correct.
      The x = 5 works fine. However,
      when x = -2 is substituted in
      and you check it on you calculator you will find that
  will
      display an error. This occurs because, if you recall, a logarithmic
      function is the inverse of the exponential function.  If you check its
      graph you will see that the argument is always positive. You cannot take
      the logarithm of a negative number. Therefore, the root x
      = -2 is called an extraneous root
      for this equation and the only root is x = 5
      .
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