Solving Polynomial Equations Using Factoring |
Answers to pre-test |
1. roots = { - 3 , - 2
,
![]() |
2. 0 is a root of both because there is no constant
term. 0 will make both equations true. |
3(a) { 0 ,
![]() |
(b) {
![]() ![]() |
(c) { - 5 , 7 } |
(d) { 1 ,
![]() |
(e) { -
![]() ![]() ![]() |
(f) { - 2 , 2 , - 2i , 2i } |
(g) { - 2 , -1 , 1 , 2 } |
(h) { 1 , 2 } |
(i) { -
![]() ![]() |
(j) { 0 , 1 , 6 } |