Solving Polynomial Equations Using Factoring |
Answers to pre-test |
| 1. roots = { - 3 , - 2
,
|
| 2. 0 is a root of both because there is no constant
term. 0 will make both equations true. |
| 3(a) { 0 ,
|
| (b) {
|
| (c) { - 5 , 7 } |
| (d) { 1 ,
|
| (e) { -
|
| (f) { - 2 , 2 , - 2i , 2i } |
| (g) { - 2 , -1 , 1 , 2 } |
| (h) { 1 , 2 } |
| (i) { -
|
| (j) { 0 , 1 , 6 } |