Answers to pre-test |
1(a)
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1(b)
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1(c)
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1(d) -2 |
1(e) 1 |
1(f)
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2(a)
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2(b)
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2(c)
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3(a)
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3(b)
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4(a)
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4(b) ![]() |
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4(c) It would be incorrect to join the points on the graph because only the values at the beginning of each day are known. No stock values are known for times during the day. | ||||||||||||||||||||||||||||||||
4(d) Domain ={1 £
day £ 15, day Î N} Range = {8 ![]() ![]() |